Father works 5 times fastr dn hs son n hence cmptl a job 40 days earlr dan son.find d time dy would take 2 finsh d job together

• Efficiency of Work ratio of father to son =5:1
  Hence ratio of time taken = 1:5
  Let f takes x days and son takes 5x days.
  Given 5x-x=40
  =>x=10 days.
  Togeter they would do part of the work in 1 day=1/10+1/50=6/50=3/25
  So tatal days eq= 25/3 days to finish the work
• 11 years agoHelpfull: Yes(20) No(0)
• Given: father is 5 times faster
  so,son will take 5 times the time taken by father.
  Suppose father takes 'x' units of time
  so son will take '5x' unit.
  
  Now,According to question
  
  5x-x=40
  4x=40
  so,x=10
  
  hence father takes 10 days and son take 5*10=50 days.
  
  so the work done in one day by both combinely = 1/10+1/50 = 6/50
  so time taken to complete the task = 50/6 =8.33
  
  =8 days 8 hours
• 11 years agoHelpfull: Yes(9) No(0)
• let son takes x days to complete the work
  father takes x/5 days and complete 40 days early so
  x-x/5=40
  x=50
  so son takes 50 days and father takes 10 days
  and simply by knowin abouve details answer is 25/3 days
• 11 years agoHelpfull: Yes(0) No(0)
• 8.33 days
  
• 11 years agoHelpfull: Yes(0) No(0)
• let son work is x. therefore fathers work is 5x. then fathers work (f=x-40)
  5x=x-40;x=10;f(5x)=50. 1/10+1/50=3/25. time=8.333
• 11 years agoHelpfull: Yes(0) No(0)