X ^ Y denotes X raised to power Y, find the last two digits (2361 ^ 4507) + (1741 ^ 3581)

• these question are solved by simple techniques....actually
  
  last two digits of 2361^4507 will
  firstly taking power of 1^..=1
  then multiplying second last digit of 2361 means 6 with last digit of power 4507 means with 7 that will be 7*6=42 .....taking last digit of 42 i.e. 2
  
  joing 2 & 1 we get 21
  similarly last 2 digit of 1741^3581=41
  
  41+21=62
  
  Answer. 62, for appropRiate proof visit tio sites related to puzzles...other than math4
• 12 years agoHelpfull: Yes(27) No(2)
• 62 it's too easy
  
• 12 years agoHelpfull: Yes(9) No(7)
• last 2 digit 61 and squering the 61,, 61^1=61,61^2=21(3721),61^3=81(226981)
  61^4=41,61^501 therefore 5terms we getting,power 4507/5=remain(2)
  41^1=41,41^2=81,41^3=21,41^4=61,41^5=01
  3581/5=remain(1)..... remain 2place value=21
  remain 1place value=41 total =62
• 12 years agoHelpfull: Yes(7) No(3)
• for here we know thatif last digit of a no. is odd except 5 then if that no is raised to a power which is multiple of 20 then last two digits will be (01).......
  now (2361)^4507=(2361)^4500*(2361)^7=> for last two digits it will be
  (61)^4*(61)^3=> (1384584141)*(226981).... if only last two digits are taken for both then it will be 41*81=3321
  having last two be 21
  and for 1741^3580*1741^1=1741
  so last two digits be 41
  now adding both we have.... 21+41=62
  thus 62 will be the last two digits
• 12 years agoHelpfull: Yes(7) No(2)
• its not easy for every1 brother .....persons who have solved these type of puzzles earlier ...they only can solve this ques....
  
  so please dont say n e thing easy.... @rishi singh
• 12 years agoHelpfull: Yes(3) No(0)
• @rishi : can u plz explain ur answer
• 12 years agoHelpfull: Yes(2) No(3)
• @rishi : plz xplain...how it came 62
• 12 years agoHelpfull: Yes(1) No(1)
• 4507/5 remainder=2
  3581/5 remainder=1
• 12 years agoHelpfull: Yes(1) No(0)
• for 2361^4507
  first take last term of 2361 which is 1
  and find 1^7=1
  now take 2nd last digit of 2361 which is 6 and here 6*7=42;
  here 7 is the last digit of 4507..
  now combine 42 and 1 which gives 421..its last 2 digits are 21-------A)
  follow this also for 1741^3581 it will give 41-------B)
  Add A+B i.e 41+21=62..
  hence correct answer is 62..
  Hope you will understand..
  
• 10 years agoHelpfull: Yes(1) No(1)
• how 10's digit of 61^4507 is comming 21..pls xplain...its not clr..any power of 6 produce 6 to?
  
• 12 years agoHelpfull: Yes(0) No(1)
• 6*7=42
  so last digit 21
  and 4*1=4
  so last digit 41
  ie ans will be=41+21=62
• 12 years agoHelpfull: Yes(0) No(2)