F(n) is a function…where f(f(n))+f(n)=2n+3.
F(n)=0;find f(2012) ?

• wrong question here f(0)=1
  then it will form a series f(0)=1
  f(1)=2;
  f(2)=3
  f(3)=4
  similary f(2012)=2013
• 12 years agoHelpfull: Yes(28) No(3)
• ans is:0.becaz f(n)=0.so,if u give any to n,then ans is=0.
• 12 years agoHelpfull: Yes(5) No(1)
• 2n+3
  f(0)+0=2n+3
  F(0)=2n+3
  so
  function not dependent on value inside bracket
  so 2n+3
• 12 years agoHelpfull: Yes(3) No(0)
• if f(n)=0
  then f(any num)=0;
  its simple
  if question is wrong
  what can i do? :)
• 12 years agoHelpfull: Yes(2) No(0)
• f(n)=0
  f(f(n))=f(0)
  f(f(n))+f(n)=f(0)=2n+3
  f(2012)=2(2012)+3=4027
  
• 12 years agoHelpfull: Yes(1) No(4)
• f(n)=0 i.e any value of n is 0.so f(2012) is also i think 0
  
• 12 years agoHelpfull: Yes(1) No(2)
• cannot solve this problem as f(0) value is not given
• 12 years agoHelpfull: Yes(1) No(1)
• Guys this is the right question.
  
  F(n) is a function. where f(f(n))+f(n)=2n+3.
  F(1)=0;find f(2012) ?
• 12 years agoHelpfull: Yes(1) No(3)