3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order IN 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 155kg then find the average weight of all the 7 rounds?

• 155 is the sum of ages of all three frnd
  here A+B+C+A+B+B+C+A+C+A+B+C=4(A+B+C)
  and we know that A+B+C=155
  hence total sum of 7 rounds = 4*155= 620
  and avg = 4*155/7
• 11 years agoHelpfull: Yes(19) No(1)
• excuse i too having tcs on coming sunday. i yet not prepared yet pls give idea to get clear aptitude. my id satheesh_mechanical@yahoo.in.......... pls friends help me
• 11 years agoHelpfull: Yes(0) No(2)
• ans is : 88.57
  
  a+b+c + a+b + b+c +b+c +a+c + a+b+c =4a+4b+4c =>4(a+b+c);
  in quest final round measume is 155 ie (a+b+c=155)
  so 4*155 =620
  ave=620/7 => 88.57
• 11 years agoHelpfull: Yes(0) No(0)
• Let the weight of A,B and C be x,y and z respectively.
  now,according to the problem,
  7 rounds weights measure are as follows-
  A-x,B-y,C-z,AB-x+y,BC-y+z,AC-x+z,ABC-x+y+z=155 kg(given) respectively,
  hence average of all the 7 rounds are-
  Average weight of 7 rounds= x+y+z+(x+y)+(y+z)+(x+z)+(x+y+z)/7
  Average=4(x+y+z)/7=4*155/7=620/7=88.5714kg.
  
  Ans=Average of all 7 rounds weight measure is 88.5714
• 11 years agoHelpfull: Yes(0) No(0)