A & B travelling from X to Y.A starts at 12 pm at a speed of 63m/hr.B at 1:30 pm at a speed of 84m/hr.At what time will be 34m ahead of A?

• A & B travelling from X to Y.A starts at 12 pm at a speed of 63m/hr.B at 1:30 pm at a speed of 84m/hr.
  
  Distance covered by A in 1.5 hrs = 63*1.5 = 94.5 mtrs.
  
  Extra distance coverd by B in 1 hr = 84-63= 21 mtrs
  Additional distance required to be covered by B so that B is 34 mtr ahead of A = 94.5 + 34 = 128.5 mtrs
  time taken = 128.5/21 = 6.12 hrs = 6 hrs 7.2 mins
  So B will be 34 m ahead of A at 7:37:12 PM
  
• 12 years agoHelpfull: Yes(15) No(0)
• Let time taken be t hrs
  Distance travelled by A in time t=63*t
  B started 90 mins late
  Time taken by B=(t-3/2)hrs
  Distance travelled by B=84*(t-3/2)
  distance of B-distance of A=34
  84(t-3/2)-63t = 34
  21t-126=34
  21t=160
  t=(160/21)hrs=7hrs 37min
  Time=12pm+ 7hrs 37 min
  =7:37 pm
• 12 years agoHelpfull: Yes(11) No(1)
• let the time taken by A be x hrs.distance =63x m.
  distance travelled by B(in x-3/2 hrs)=84(x-3/2)
  84(x-3/2)-63x=34
  x=7hrs 36 min
  thus d time 7 hrs 36 min ahead of 12pm z 7:36 pm..
• 12 years agoHelpfull: Yes(1) No(0)