there are two boxes,one containing 10 red balls and the other containing 10 green balls.you are allowed to move the balls between the boxes so that when you choose a box at random and a ball at random from the choosen box,the probability of getting a red ball is maximized.the maximum probability is

• to maximize probability,we will allow 9 red balls to mix in box containing green balls
  So,one box contains 1 red ball
  other contains 10 green & 9 red
  If 1st box is chosen randomly,
  Probability of taking 1st box=1/2
  Probability to get red ball=1 of 1/2=1/2
  If 2nd box is chosen randomly
  Probability of taking 2nd box=1/2
  Probability to get red ball=9/19 of 1/2=9/38
  Total probaility=1/2+9/38=28/38=14/19
  Maximum probability = 14/19
  
  
• 12 years agoHelpfull: Yes(30) No(2)
• for this q u have a simple formula which s applicable for al these type of q.. it s 1/2+1/2((no. of max balls -1)/(total no of balls -1))..
  so here max ball is red = 10 and total balls = 20.. if u substitute dis u wil get the ans....:)
• 12 years agoHelpfull: Yes(1) No(0)
• 10C1/20C1
  
• 12 years agoHelpfull: Yes(0) No(10)
• maximum prob=9/19
• 12 years agoHelpfull: Yes(0) No(6)