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if a 250m long train crosses a platform of the same length as that of the train in25seconds,then the speed of the train is
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- total length covered in 25 sec=250+250=500m
thus speed=500/25=20m/s
- 12 years agoHelpfull: Yes(10) No(0)
- total distance covered by train to cross platfrm [d] =250(length of train)+250 (length of platfrm)
therefore d=500 m
time taken to cover distance [t] = 25 sec
speed = d/t=500/25= 20 .....ans - 12 years agoHelpfull: Yes(4) No(0)
- total distance travelled=250*2=500m
time=25sec.
speed=500/25=20m/s - 12 years agoHelpfull: Yes(3) No(0)
- time =(length of train + length of platform)/speed of train
ans = 20m/s - 12 years agoHelpfull: Yes(3) No(0)
- Speed=total distance / time
[250+250]/20
Gives 20 m/s....... - 12 years agoHelpfull: Yes(2) No(0)
- 72 km/hr...:)
- 12 years agoHelpfull: Yes(1) No(3)
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