N=9+X+Y-Z, X,Y,Z(- 0-9, A wants to maximize and b wants 2 minimize, maximum value of N=? if A turns 1st...

• Ans is 20
  X=6 or X=8 or X=5
  Y=9 Y=9 Y=9
  Z=4 Z=6 Z=3
  
  using this strategy only we will get the optimal result!!!!!The whole strategy depends on the first no!!!!
  If we choose a no bigger than 5 or 6 it will make N minimum.
  If we choose a no smaller than 5 or 6, N will not be maximised.
  
  and whatever no is chosen by A at the second time, B will have to put it in Z because if he wont, A will choose the last no as 0 and the varible Z will be of no use then
• 12 years agoHelpfull: Yes(10) No(0)
• ans= 18.
  
  as A wnt to maximize so A always slct max no.(9)n B placed it on any variable like
  fist in place of Z thn again A select 9 n B placed it on any variable....
  so eq. become 9+9+9-9 = 18. ANS....
• 12 years agoHelpfull: Yes(5) No(4)
• check at
  http://www.m4maths.com/416-alok-n-bhanu-play-the-following-min-max-game-N-9-X-Y-Z-so-wer-x-y-z-are-variables.html
  
  Puzzle no
  (#M40000416)
• 12 years agoHelpfull: Yes(1) No(0)
• 9+9=18
  ans
• 12 years agoHelpfull: Yes(0) No(3)
• 9+9+8-7=19
• 12 years agoHelpfull: Yes(0) No(1)
• 18 i suppose
• 12 years agoHelpfull: Yes(0) No(2)