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Probability
. coins of 1,2, 5 rupees are tossed , what is the probability of getting a head on 1,tail on 2 and head on 5 rupee.
(a) ½ (b) ¼ (c) 1/8 (d) 1/16
Read Solution (Total 13)
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- ans : 1/8
any coin probability of getting H or T is 1/2
so 1/2 *1/2 * 1/2 = 1/8
- 12 years agoHelpfull: Yes(19) No(3)
- probablity of getting head on re 1= 1/2
probablity of getting tail on rs 2= 1/2
probablity of getting head on rs 5= 1/2
so net probablity= 1/2*1/2*1/2=1/8 - 12 years agoHelpfull: Yes(8) No(1)
- frns hw cme ans vill b 1/8....sample space 4r tossing 3 coins is 8 na...nd den probabity 4r head on 1rupee is 1/2 ndtail on 2rupees is 1/2 nd head 5rupees is also 1/2...now net prababity shud b (1/2*1/2*1/2)/8 i.e 1 na?
- 12 years agoHelpfull: Yes(1) No(3)
- SAMPLE SPACE FOR TOSSING 3 COINS IS 8
HEAD ON 1ST COIN, TAIL ON 2ND COIN,HEAD ON 3RD THAT IS (H,T,H) WHICH IS 1 SPACE
SO PROBABILITY IS 1/8 ... - 12 years agoHelpfull: Yes(1) No(1)
- for the outcome of 3 coins, we will have 2^3 possibility(coins are in the order 1,2,5):
HHH,HHT,HTH,HTT,THH,THT,TTH,TTT.
FROM THE ABOVE , only 3rd condition follows the question.
so , ans:1/8 - 12 years agoHelpfull: Yes(0) No(0)
- guys mutually exclusive events... so 1/2 is the answer i think...
- 11 years agoHelpfull: Yes(0) No(2)
- 1/8
Because 8 possibilities are there and only 1 meets the condition. - 10 years agoHelpfull: Yes(0) No(0)
- probability of getting H(1) = 1/2
probability of getting T(2) = 1/2
probability of getting H(5) = 1/2
Hence total Probability = 1/2 * 1/2 * 1/2
= 1/8
- 10 years agoHelpfull: Yes(0) No(0)
- sample space =8
the condtion according to question is ......HEAD TAIL HEAD (HTH)
number of event =1
probability=event/sample space=1/8,..............:) - 8 years agoHelpfull: Yes(0) No(0)
- (1/2)*(1/2)*(1/2)=1/8
- 8 years agoHelpfull: Yes(0) No(0)
- ans:1/8
because any coin probability of getting H or T IS 1/2
SO COIN OF 1 rupees probability is 1/2
coin of 2 rupees probability is 1/2
coin of 5 rupees probability is 1/2
then total probability is 1/2*1/2*1/2=1/8 - 8 years agoHelpfull: Yes(0) No(0)
- the solution is 1/8
i.e; 1/2*1/2*1/2=1/8 - 5 years agoHelpfull: Yes(0) No(0)
- According to the problem,
Sample space is
There are two heads, one tail and the total smaple space is three.
So getting head or tail is
Thus, getting head on the is
Getting tail on the is
Getting head on the is
Thus, probability is
Hence, the probability of getting head on the , tail on the and a head on the coins is - 5 Months agoHelpfull: Yes(0) No(0)
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