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If abc4d is divisible by 4, then d cannot be
(a) 0 (b) 4 (c) 8 (d) 2
Read Solution (Total 6)
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- ANS:(d)
40,44,48 is divisible by 4.
not 42. hence d cannot be 2 - 12 years agoHelpfull: Yes(18) No(1)
- for divisiblity of any no by 4 last two digit must be divisible by 4 and by putting 2 in place of d we see that no come 42 which is not divisible by 4
so ans is d - 12 years agoHelpfull: Yes(3) No(0)
- condition for divisibulity by 4 is last 2 digits shud be divisible by 4 so
in above prob if we replace d by 0,4,8 they are divisible by 4
so ans:2 - 12 years agoHelpfull: Yes(1) No(0)
- FOR d TO BE NOT DIVISIBLE BY 4 , THERE IS DIVISIBILITY RULE FOR 4 WHICH SAYS THE LAST TWO DIGITS SHOULD BE DIVISIBLE BY 4.
SO 40 , 44 , 48 ARE DIVISIBLE BY 4 BUT 42 IS NOT DIVISIBLE - 12 years agoHelpfull: Yes(0) No(0)
- For a number to be divisible by 4, the last two digits should be divisible by 4. So, the last two digits are 4d. Except option (d), other options are divisible by 4.
- 3 years agoHelpfull: Yes(0) No(0)
- For a number to be divisible by 4, the last two digits should either be two zeros (00) or a number that would be divisible by 4.
We have been given abc4d as the number,
For this number to be divisible by 4,
Case 1:
The last two digits of the number should have been 00
which is not the case.
Case 2:
The last two digits should be a number divisible by 4
The second last digit is given as 4.
Hence, the last digit that is d can now be only 0,4, or 8.
Since 40,44 and 48 will only be the numbers divisible by 4. - 5 Months agoHelpfull: Yes(0) No(0)
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