A bag contains 1 rupee 2 rupees and 5 rupees coins in the ratio 4:8:5. The Total Amount was Rs.90. The number of 5 rupee coin was
(a) 8 (b)16 (c)15 (c) 10

• let the 1rupee 2rupee and 5 rupee coins be in the ratio 4x,8x,5x
  According to question,4x*1+8x*2+5x*5=90
  4x+16x+25x=90
  45x=90=>x=2
  thus the no 5 rupee coin is=5*2
  =10
• 12 years agoHelpfull: Yes(35) No(2)
• ans : 10
  
  1*4 + 8*2 + 5*5 = 45
  
  to make it 90
  
  we need same ratio of coins
  
  so total no.of 5rs coins = 10
  
• 12 years agoHelpfull: Yes(4) No(6)
• Ans:10
  Assume by
  just taking the given ratio 4:8:5 = 4(1 rupees)+8(2 rupees)+5(5 rupees)=45
  we need 90, double(multiply by 2 ) the given terms (4,8,5)=(8,16,10)
  so[ 8(1 rs)+ 16(2 rs)+10(5 rs)=90 ]
  10 (5 rupees) coin needed
  
• 12 years agoHelpfull: Yes(2) No(0)
• 10
  4x+16x+25x=90
  x=2
  so,5x=5*2=10
• 12 years agoHelpfull: Yes(0) No(0)
• option c.10 =>1*8+8*4+5*10=8+32+50=90.
• 12 years agoHelpfull: Yes(0) No(1)
• 10
  4x+8x+5x=90
  x=2
  5*2=10
• 10 years agoHelpfull: Yes(0) No(0)
• coin are n ratio 4:8:5
  1 rs coin*4=4rs
  2rs coin*8=16rs
  5rs coin*5=25rs
  4+16+25=45rs
  2(4+16+25)=90rs
  ans is 10
• 10 years agoHelpfull: Yes(0) No(0)
• if there were 10 coins it means the 5 rupee coins were 5*2 coins and amount of 50/- then 2 rupees of 8*2 coins and amount to 32/-
  and then 1 rupees of 4*2 coins and amount to 8/-
  so total of 90/-
• 10 years agoHelpfull: Yes(0) No(0)
• the answer will be 10
  if the ratio is 4:8:5 let the num of coins would be 8:16:10
  then the summ will be 8*1+16*2+10*5=90
• 10 years agoHelpfull: Yes(0) No(0)
• 10 option c
• 10 years agoHelpfull: Yes(0) No(0)
• 4x:8y:5z
  x,y,z are means 1,2,5 rupee coins
  4(1)a+8(2)a+5(5)a=90
  4a+16a+25a=90
  45a=90
  a=2
  so 5a=No of coins in % rupee coins
  so 5a=10 a=2
• 9 years agoHelpfull: Yes(0) No(0)
• suppose common multiplier for the ratio is x.
  vallue of total 1 rupee coins is 4x,2 rupee coins is 16x and 5rupee coins is 25x.so 4x+16x+25x=90.
  so x=2 so number of 5 rupee coin is 5*2=10. ans is (d)10.
• 7 years agoHelpfull: Yes(0) No(0)
• let the 1rupee 3rupee and 5rupee coins be in the ratio 4x,8x,5x
  a/q 4x*1+8x*2+5x*5=90
  4x+16x+25x=90
  45x=90
  x=2
  then no of 5 rupee coins =5x
  = 5*2=10
• 7 years agoHelpfull: Yes(0) No(0)
• 1 R 2R 5R
  4 x : 8 x : 5x
  1*4x+2*8x+5*5x=90
  45x=90
  x=2
  now no of 5 rupee coins =5x
  =5(2)
  =10
• 6 years agoHelpfull: Yes(0) No(0)