Q. 9x^2+3px+6q divided by 3x+1 leave reminder -3/4 and qx^2+4px+7 is exactly divisible by x+1, then find the values of p and Q

• ans q=0 p=7/4
  
  put value of x=(-1/3) in equation1-remainder. put valueof x=-1 in second equation . then solve to get the ans.
  
  
• 12 years agoHelpfull: Yes(30) No(8)
• 1st quadration eqn gives remainder -3/4 on dividing by 3x+1.so, eqn-(-3/4) is divisible by 3x+1 means eqn+3/4 has a roo x=-1/3.so,on putting x=-1/3 in the 1st eqn,1-p+6q+3/4=0 that is 6q-p=-7/4.2nd quad eqn is divisible by x+1.so x=-1 is root of that eqn.on putting x=-1,eqn=0.so,
  q-4p+7=0.on comparing two linear eqns in p and 2,we get p=7/4 and q=0.
• 12 years agoHelpfull: Yes(21) No(0)
• q= 6/23
  p=167/92
• 12 years agoHelpfull: Yes(1) No(14)
• if some has right ans then please tell me
• 12 years agoHelpfull: Yes(1) No(2)
• Pls send me the previous year papers on snehaa34@gmail.com
  Pls tell about the recent papers.
• 12 years agoHelpfull: Yes(1) No(3)
• p=7/4, q=0
• 12 years agoHelpfull: Yes(1) No(3)
• Best Method For This is..... Simple go with options...
• 10 years agoHelpfull: Yes(1) No(2)
• p= 1 ; q = 3 ; x= 2
  now put the value of p,q ... u get the result...!!!!
• 12 years agoHelpfull: Yes(0) No(3)