12 machines can complete a work min 20days. 4 machines found to be defective working.the no. of days required to complete the task is?

• n1*d1=n2*d2
  12*20=8*x
  x=30
• 12 years agoHelpfull: Yes(19) No(0)
• if 12 machines do it in 20 days
  1 machine would do it in 20*12= 240 days
  So, 8 machines would do it in 240/8= 30 days
  ans = 30
• 12 years agoHelpfull: Yes(8) No(0)
• 12 mac do a work in=20 days
  so 1 mac will do it in=20*12
  1 day work of mac=1/240
  8 mach are in working state
  let they tak x day to complet the work
  x*8/240 =1
  240/8=x
  30 days
• 12 years agoHelpfull: Yes(6) No(0)
• 30 daz.tiu;upo[pifghjk
• 12 years agoHelpfull: Yes(0) No(0)