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11. 1032A book is published once in every 10 years starting from its origin, sum of the first ten years in which the book is published is 19560, then the year in which the first copy of the book was printed is
a. 1909
b. 1910
c. 1911
d. 1912
Read Solution (Total 5)
-
- 1st yr= a
10th yr = a+(n-1)d= a+(10-1)*10=a+90
Sn= 10*[a+(a+90)] /2 = 10a+450
10a+450 = 19560
10a=19110
a=1911
- 9 years agoHelpfull: Yes(5) No(0)
- 1911
from 1911 ,1921,1931,count up to 2001 - 9 years agoHelpfull: Yes(1) No(2)
- 1910, sum of 10 years must be divisible by 10
- 9 years agoHelpfull: Yes(0) No(1)
- ans is 1910.
- 9 years agoHelpfull: Yes(0) No(0)
- 1909 is th answr
- 9 years agoHelpfull: Yes(0) No(0)
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