How many 6 digit even numbers can be formed by using 1, 2, 3, 4, 5, 6 and 7 such that the second last digit is even?

• 5p4*2*3=720
• 9 years agoHelpfull: Yes(10) No(3)
• second last digit can be filled in 3 ways. so - - - - 3 - .
  now first digit in 6 ways, second in 5 ways , third in 4 ways , fourth in 3 ways, fifth means second last in 3 ways and last in 2 ways. so overall, 6*5*4*3*3*2=2160
  so ans is 2160.
  
• 9 years agoHelpfull: Yes(7) No(0)
• pls tell which one is correct
• 9 years agoHelpfull: Yes(1) No(0)
• second last digit can be either 2, 4 or6 i.e 3 ways
  so total no of ways= 6!*3=2160
• 9 years agoHelpfull: Yes(0) No(0)
• 5!/3!
  135 (246) 7-(246)one number.therfore 5 numbers.
• 9 years agoHelpfull: Yes(0) No(0)
• By observing clearly, he is asking the number of 6 digit even numbers which ends a pair of even numbers
  _(2) _(3) _(4) _(5) _(2) _(3)
  Term in the open brackets represents number of ways of filling the 6th,5th,....,1st blank.
• 9 years agoHelpfull: Yes(0) No(0)