22. A can of 100 lts contains 50%milk and another can of capacity 300 lts contains (2/3)rd milk remaining volume of both the cans is filled with water. Now these two liquids are poured in to a drum whose volume is more than the sum of these two cans. The %of milk in the drum is?

• Total Milk=50+200=250 lit
  Total Mixture=100+300=400 lit
  % of milk in mixture= (250/400)*100 =62.5
• 9 years agoHelpfull: Yes(5) No(0)
• 50% milk in 100L,so quantity of milk in 100L is 50L
  2/3rd of milk present in 300L,so quantity of milk in 300L is 200L
  total quantity of milk is 250L in 400L=(250/400)*100=62%
• 9 years agoHelpfull: Yes(3) No(1)
• 50/100 * 33.33/100*400= 66.67
  
  
• 9 years agoHelpfull: Yes(0) No(2)