A B C can do a piece of work in 36 days A B together are twice as efficient as

ans is 108
9 years agoHelpfull: Yes(0) No(1)
a+b+c=1/36
a+b=2c,=>2c+c=1/36=>3c=1/36=>c=1/36*3=1/105
c alone finish in 108 days
9 years agoHelpfull: Yes(0) No(0)
A + B + C = 1/36
A + B = 2*B
A + B + C = 3*C
so according to the above,
3*C = 1/36
C = 1/108
so C alone can do that work in 108 days.
9 years agoHelpfull: Yes(0) No(0)
there ratio SUM up to 2+1+3 i.e., 6 ...
so c can do in 36*3= 108 days
9 years agoHelpfull: Yes(0) No(0)
Workers A+B+C A+B=2C A+C=3B A+B+C=2C+C=3C
Days 36 _ _ 36

If 3C can complete work in 36 days,
Therefore, C can complete it in 36*3=108 days.
9 years agoHelpfull: Yes(0) No(0)
a+b+c=36
a+b=2c
a+c =3b
solve 2 and 3 we get
-a+7b=0
7b=a--------------4
apply 4 in 2 we get 4b=c-----------5
apply 4 and 5 in we get
a=21
b=3
c=12
so the days for b is 36*3=108
9 years agoHelpfull: Yes(0) No(0)

A,B,C can do a piece of work in 36 days A,B together are twice as efficient as C. A,C together are thrice as efficient as B. In how many days c alone can do that work.