Which of the following has the same calendar as 2005?
a) 2008
b) 2010
c) 2011
d) 2012

• assume 1st jan 2005----- 0 day
  2008 1st jan --------- 2005+3 years= 3 odd days ie., not the same day
  2010 1st jan --------- 5 odd days not the same
  2011 1st jan --------- 6 odd days not the same
  2012 1st jan --------- 7 odd days means 0 odd days have same day as 1st jan of 2005
• 9 years agoHelpfull: Yes(3) No(1)
• Its 2011 Chack both the calenders.
  Also 2008 will have 4 odd days due to leap year.
• 9 years agoHelpfull: Yes(3) No(0)
• x/4 ( x=given year)
  for any year divided by 4, the possibility of remainders are 0,1,2,3.
  if remainder is 0---->x+28
  if remainder is 1---->x+6
  if remainder is 2 (or) 3------>x+11
  
  Ans: 2005/4=1(remainder)
  
  2005+6=2011
  
• 9 years agoHelpfull: Yes(3) No(0)
• 2012 is the answer.....
• 9 years agoHelpfull: Yes(2) No(2)
• Its 2011 Check both the calenders.
  Also 2008 have 4 odd days due to leap year.
  
• 9 years agoHelpfull: Yes(2) No(0)
• ANS is c) 2011
  
  find out for same calender
  rule follow only range( 1901 to 2071)
  if remander is 1= 6 year add in next yr
  remender is 2= 11 year add in next yr
  remender is 3= 11 year add in next yr
  remender is 0= 28 year add in next yr
  
  example same calender as 2005
  2005/4== rem(1) then add 6year in 2005+6=2011 as next same calender
  
• 9 years agoHelpfull: Yes(1) No(0)
• plz explain
• 9 years agoHelpfull: Yes(0) No(0)