TCS
Company
If p, q, r and s are nonzero numbers such that p and q are the roots of the quadratic x2 + rx + s = 0 and r and s are the roots of the quadratic x2 + px + q = 0, then p + q + r + s =
2
-2
0
4
(-1 + √5)/2
Read Solution (Total 6)
-
- we have p+q=-r...(1)
and r+s=-p...(2)
from 1 and 2 we have
s=q.... (3)..
also from the 2nd quadratic equation we have
rs=q but we have found out that s=q therefore
r=1...(4)
and similarly p=1...(5)
putting the value of r and p in equation 1 and 2 we get s and q as -2 respectively.
thereforep+q+r+s=1-2+1-2= -2 ans - 12 years agoHelpfull: Yes(25) No(2)
- @niki:
if there is a equation ax^2+bx+c=0
and the roots are A and B (let)
then A+B=-(b/a)
and A*B=(c/a)
rest part is explained by DIPEN JAIN
hope it will help u :) - 12 years agoHelpfull: Yes(10) No(1)
- -2 may be the ans
- 12 years agoHelpfull: Yes(1) No(2)
- @snehil- pls explain
- 12 years agoHelpfull: Yes(0) No(0)
- @snehil ,@ dipen: thnk u..:)
- 12 years agoHelpfull: Yes(0) No(0)
- -2 aftr getting all, the p,q,r,s values
- 11 years agoHelpfull: Yes(0) No(0)
TCS Other Question