If p, q, r and s are nonzero numbers such that p and q are the roots of the quadratic x2 + rx + s = 0 and r and s are the roots of the quadratic x2 + px + q = 0, then p + q + r + s =

2
-2
0
4
(-1 + √5)/2

• we have p+q=-r...(1)
  and r+s=-p...(2)
  from 1 and 2 we have
  s=q.... (3)..
  also from the 2nd quadratic equation we have
  rs=q but we have found out that s=q therefore
  r=1...(4)
  and similarly p=1...(5)
  putting the value of r and p in equation 1 and 2 we get s and q as -2 respectively.
  thereforep+q+r+s=1-2+1-2= -2 ans
• 11 years agoHelpfull: Yes(25) No(2)
• @niki:
  if there is a equation ax^2+bx+c=0
  and the roots are A and B (let)
  then A+B=-(b/a)
  and A*B=(c/a)
  rest part is explained by DIPEN JAIN
  hope it will help u :)
• 11 years agoHelpfull: Yes(10) No(1)
• -2 may be the ans
• 11 years agoHelpfull: Yes(1) No(2)
• @snehil- pls explain
  
• 11 years agoHelpfull: Yes(0) No(0)
• @snehil ,@ dipen: thnk u..:)
• 11 years agoHelpfull: Yes(0) No(0)
• -2 aftr getting all, the p,q,r,s values
  
• 10 years agoHelpfull: Yes(0) No(0)