In a 1500 race, Tinu beats Minu by 150 m and in the same race Minu beats Rinu by 75 m. by what distance does Tinu beat Rinu?
a) 210.5 m
b) 217.5 m
c) 213.5 m
d) 225 m

• --------------------Rinu(1275m)-----------minu(1350m)---------tinu(1500m)
  Tinu beat Rin by 150+75=225m
• 9 years agoHelpfull: Yes(17) No(5)
• 217.5m will b the ans
• 9 years agoHelpfull: Yes(8) No(4)
• b) 217.5
  
  A : B = 1500 : 1350
  
  B : C = 1500 : 1425
  
  A : C =(A/B) * (B/C)
  = (1500/1350) * (1500/1425)
  = (10/9) * (1500/1425)
  => ( 10*1500 : 1425*9)
  = 1500 : 1425 *(9/10)
  = 1500 : 1282.5
  A beats C by (1500 - 1282.5) m = 217.5 m.
• 8 years agoHelpfull: Yes(5) No(0)
• D) AS per qus > T/M=1500/1350 & M/R=1350/1275 thn T/R=T/M*M/R >> 1500-1275=225meter
  whr , T,M,R=tinu,minu,rinu
• 9 years agoHelpfull: Yes(4) No(2)
• ans is 217.5
  ratio of speed b/w tinu minu and rinu respectively-200:180:171
  diff b/w tinu &minu speed in ratio 20 parts
  diff in ratio b/w minu&rinu=29 prts
  20parts=150 (given)
  then 29 parts=217.5
  only sol....
• 9 years agoHelpfull: Yes(1) No(0)