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Numerical Ability
Permutation and Combination
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how many triangles are possible using above points?
Read Solution (Total 9)
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- 15C3 - 5*3C3 - 3*5C3 = 420
- 9 years agoHelpfull: Yes(5) No(2)
- 15C3 =455
them their are 3 rows and 5 column i.e:455-43=412 - 9 years agoHelpfull: Yes(5) No(1)
- 15C3 = 455
- 9 years agoHelpfull: Yes(4) No(5)
- total no. of possible triangles=15c3
in row 5 points are in straight line and in column 3 points are in straight line.
so ans=15C3-3*5C3-5*3C3=420 - 9 years agoHelpfull: Yes(2) No(1)
- 15C3 - (3*5C3) -(5*3C3) - 6=414
- 9 years agoHelpfull: Yes(2) No(0)
- there are 15 points so the number of possible triangles are 15C3=455
- 9 years agoHelpfull: Yes(0) No(4)
- 394
455-(5+50+6)
- 9 years agoHelpfull: Yes(0) No(0)
- guys it should be 414 @sangita dutta you made correct approach but there was calculation mistake..:)
- 9 years agoHelpfull: Yes(0) No(0)
- I think the ans is 414
out of 455 chances we cannot make triangle in 36 ways so 455-36=419
3+3 chances in diagonal
10+10+10 in Straight line Like . . . . . any 3 points from this five cannot from triangle so 5c3 *3
1+1+1+1+1 for . there are 5 chances that cannot make triangle
so 414 chances we can make triangle
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. - 9 years agoHelpfull: Yes(0) No(0)
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