7. x takes 4 days to complete one third of a job, y takes 3 days to complete one sixth of the
Same job and z takes 5 days to complete half of the job.If all of them work together for 3 days and x and z quit, how long will it take for y to complete the remaining work done?

• x takes 4*3=12 days to complete the job=> work done in 1 day=1/12
  y takes3*6=18 days to complete the job=> work done in 1 day=1/18
  z takes 5*2=10 days to complete the job=> work done in 1 day=1/10
  Work done by all of them in 3 days=3*(1/12+1/18+1/10)
  =3*(15+10+18)/180
  =43/60
  work left=17/60
  if y takes a days,
  work done=a*1/18=17/60
  =>a=(17*18)/60
  =>a=5.1 days
  
• 12 years agoHelpfull: Yes(41) No(2)
• x takes 4 days to complete one third of a job, y takes 3 days to complete one sixth of the
  Same job and z takes 5 days to complete half of the job.
  x takes 12 days to complete a job, y takes 18 days to complete the
  Same job and z takes 10 days to complete the job.
  
  3 days job when they work together = 3*( 1/12 = 1/18 + 1/10) = 43/60
  Balance work (17/60) is done by Y in 18*17/60 = 51/10 = 5.1 days
• 12 years agoHelpfull: Yes(6) No(2)
• work done by x in 1day=1/12
  work done by y in 1day=1/18
  work done by z in 1day=1/10 LCM of 12,18,10 is 180.
  so,x does =>1/12*180=15,y does=>1/18*180=10,z does =>1/10*180=18
  work done by x,y,z in 1day=15+10+18=43
  work done by x,y,z in 3day=3*43=129 after 3 days x and z quit so,
  remaining work=180-129=51
  work done by y in 1day=10
  so y complete the work in 5.1days
• 12 years agoHelpfull: Yes(5) No(1)
• X=>4*3=12
  Y=>6*3=18
  Z=>5*2=10
  3*(1/12+1/18+1/10)+remain/18=1
  (Formula: A did/A can + B did/B can=1)
  (Here,3(1/X can+1/Y can+1/Z can)+remain/Y can=1)
  remain=5.1
  
• 12 years agoHelpfull: Yes(2) No(1)