10. The sum of three consecutive numbers of 4 numbers A,B,C and D are 4613,4961,5010 and 5099, then what is the largest number among A,B,C,D?

• Let, S1,S2,S3,S4 be the sums of A,B,C,D taking 3 of them at a time.
  :
  S1+S2+S3+S4 = 4613+4961+5010+5099
  S1+S2+S3+S4 = 19683....[1]
  let
  S1= A+B+C
  S2= B+C+D
  S3= C+D+A
  S4= D+A+B
  -------------------------------------------------------
  adding the above terms we get,
  S1+S2+S3+S4 = 3(A+B+C+D)
  =>19683 = 3(A+B+C+D); [From [ 1] ]
  =>(A+B+C+D)=(19683/3)
  =>(A+B+C+D)=6561
  
  So,the greatest term among them =sum of all four - sum of lowest three terms
  So,the greatest term among them=6561-4613 = 1948.
  
  So,the greatest term among them = 1948
• 12 years agoHelpfull: Yes(52) No(0)
• I think the numbers A,B,C,D are not consecutive.
  
  Pls check.
• 12 years agoHelpfull: Yes(3) No(4)
• D is the largest number having value=1948
• 12 years agoHelpfull: Yes(1) No(0)