if the equatn A+B+C+D+E=FG is two digit numbers,whose value is 10f+G and the
letter A,B,C,D,F and G each represent diffrent
gigits. if FG is as large as posible,what is the value of G?

• A+B+C+D+E=FG
  E=9,D=8,C=7,B=5,A=2
  
  A+B+C+D+E=FG = 31
  
  G=1
• 12 years agoHelpfull: Yes(22) No(3)
• A=9, B=8, C=7, D=6,E=5
  
  A+B+C+D+E= 35= FG
  
  G=5 (after summation of 5 different DIGITS, FG is highest possible no. of two different digits)
• 12 years agoHelpfull: Yes(6) No(8)
• A+B+C+D+E=FG
  E=9,D=8,C=6,B=5,A=4
  then A+B+C+D+E=32
  so ans is g=2
• 12 years agoHelpfull: Yes(6) No(0)
• If A,B,C,D,F and G each represent different digits.
  then
  max value of FG is 31
  and hence G=1.
  E=9,D=8,C=7,B=5,A=2
  F=3, G=1
• 12 years agoHelpfull: Yes(4) No(0)
• G=8,
  for the two digit larger number with different digits=98
• 12 years agoHelpfull: Yes(2) No(11)
• here condition given repetition isn't allowed so a=9,b=7,c=7,d=6,e=5 a+b+c+d+e=32
  in the sum we wil take it as f=3 nd g=2 soooo g value now 2
• 12 years agoHelpfull: Yes(2) No(7)
• E=9,D=8,C=7,B=6,A=5
  A+B+C+D+E=35(FG)
  G-5
  
• 12 years agoHelpfull: Yes(1) No(11)
• 1+3+7+5+8=24...so last digit i.e G=4..i think so
• 12 years agoHelpfull: Yes(1) No(5)
• A=9,B=8,C=7,D=5,E=5
  A+B+C+D+E=34
  G=4
• 12 years agoHelpfull: Yes(0) No(1)
• is E repeatable in the question???
• 12 years agoHelpfull: Yes(0) No(0)
• consider a,b,c,d,e as 1st,2nd,3rd,4th and 5th place's degits.
  So,1+2+3+4+5=15
  a+b+c+d+e=fg
  comparing,
  f=1 and g=5
  Also,15=10*1+5
  ie.fg=10f+g
• 12 years agoHelpfull: Yes(0) No(1)
• ans is 6..
  
• 12 years agoHelpfull: Yes(0) No(0)