From a pack of cards. 2 cards are chosen at random. Find the probability of the event of having one card as 10 which is not hearts and another a hearts cards

• (3c1*13c1)/52c2=1/34
• 12 years agoHelpfull: Yes(24) No(1)
• (3c1*12c1)/(52c2) = 6/221
• 12 years agoHelpfull: Yes(7) No(2)
• (3C1*13C1)/52C2
  as the second card selected can be a "10" of hearts.
  which gives : 3/68
• 12 years agoHelpfull: Yes(4) No(3)
• 3C1*13C1/52C2=1/34
• 12 years agoHelpfull: Yes(4) No(0)
• 4/13..
  is the right ans
• 12 years agoHelpfull: Yes(2) No(4)
• 3c2*12c1/52c2
  bcoz ist casecan be 3c2
  but 2nd a case of 10 heart must be removed from 13 red heart bcoz if any one of the card become 10 heart thenfrom given two condition one condition become invalid
• 12 years agoHelpfull: Yes(0) No(3)
• please send tcs patterns to this mail rajesh24.ur@gmail.com
  
• 12 years agoHelpfull: Yes(0) No(0)