There are some chicken in a poultry. They are fed with corn. One sack of corn will come for 9 days. The farmer decides to sell some chicken and wanted to hold 12 chicken with him. He cuts the feed by 10% and sack of corn comes for 30 days. So initially how many chicken are there?

• x*y=1/9 and 12*y*0.9 =1/30. solve two equations by dividing second by first.we get x =36. where x = no. of chickens and y = intake of fodd per day.
• 15 years agoHelpfull: Yes(9) No(0)
• 36
• 15 years agoHelpfull: Yes(4) No(0)
• x chicken * 9 days = 10.8 chicken * 30days
  x=10.8*30/9 = 36
  he had 36 chicken)x chicken eat 1 sack per 9 days
  then he keeps 12, but cuts the feed by 10%,
  so the 12 chicken now eat as 12-10%=10.8 chicken would have before
  so 10.8 chicken eat a sack per 30 days
• 12 years agoHelpfull: Yes(3) No(4)
• hannnnnnnnnnn ...hannnnnnn 36
  
• 8 years agoHelpfull: Yes(1) No(4)
• Let x be the number of chickens
  Per day consumption = 1/9 Sack, Consumption of a chicken per one day = 1/9x.
  12 chickens needs 12/9x sack of corn.
  After 10 % feed cut consumption per day becomes (.9) 12/9x. For 30 days = (30) (.9) 12/9x
  Equating this to 1 sack, we get x = 36
• 2 years agoHelpfull: Yes(0) No(0)