TCS
Company
carl covers a certain distance by car.he divides the complete distance into four equal parts and after finishing each part he increased his speed to twice the previous one. if, in the first part his speed was 30kmph then what is the average speed of the complete journey?
Read Solution (Total 4)
-
- If total distance was 4x, then
total time taken = x/30 +x/60 + x/120 +x/240 = 15x/240= x/16
Average speed = 4x/(x/16) = 64 kmph - 12 years agoHelpfull: Yes(28) No(3)
- 1st 1/4 distance his speed is 30kmph,2nd 1/4 distance his speed is 60kmph so the avg speed is 40kmph. 3rd 1/4distance his speed is 120kmph, 4th 1/4 distance his speed is 240kmph, so the avg is 160kmph .For finding avg speed for 40kmph and 160kmph is ANS: 64kmph
- 12 years agoHelpfull: Yes(4) No(3)
- assume total dt=120
1st hr he'll reach in 1 hr,2nd in 30mts,3rd in 15mts,4th in7.5mts.
avg speed=120/(1+1/2+1/4+1/8)
=64kmph. - 12 years agoHelpfull: Yes(1) No(0)
- i think 64 km/h
- 12 years agoHelpfull: Yes(0) No(0)
TCS Other Question