Others Maths Puzzle

1,3,9,_,16900

Read Solution (Total 2)

1,3,9,_,16900 seems wrong.

If series is
1,2,9,_,16900

then final series will be

1,2,9,121,16900

9=(1+2)^2
121= (2+9)^2
16900= (9+121)^2
12 years agoHelpfull: Yes(13) No(0)

121
1,3,9,_,16900 seems wrong.

If series is
1,2,9,_,16900

then final series will be

1,2,9,121,16900

9=(1+2)^2
121= (2+9)^2
16900= (9+121)^2
9 years agoHelpfull: Yes(0) No(0)

Others Other Question

A four digit number (not beginning with 0) can be represented by ABCD. There is one number such that ABCD=A^B*C^D, where A^B means A raised to the B power. Can you find it? lm, .;/ml ;