m4math Maths Puzzle Category

x, y and z are three positive integers such that x not= y not= z and 0 < x < y < z < 10; If x+y+z = 15 then number of possible pairs of (x, y, z) will be

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m4math Other Question

My score is following
Ps-95
Quant-94.44
Verbal-35
What are my chances
Last two digit of the number (129)^129 will be