‎0,1,2,3 use these numbers for 4digit numbers and find the sum?

• total no of no's possble are: 18, as "0" cannot occur at 1st place.
  (n-1)!*sum of digits * 1111
  3!*6*1111=39996
  but sum of no's formed when 0 is at 1st place should be subtracted,
  39996 - (2!*6*111)
  39996 - 1332
  38664.
  if any doubt, form 4 digit no's and add them, no's are:
  1023,1032,1203,1230,1302,1320, 2013,2031,2103,2130,2301,2310, 3012,3021,3102,3120,3201,3210
  add them,will result to: 38664
• 11 years agoHelpfull: Yes(41) No(1)
• the total combinations possible are 4!=24..if we write the combinations one after the other we get 24 rows and 4 columns..in each column we will hav 6 zeroes,6 ones,6 twos and 6 threes=> each column counts=(6*0+6*1+6*2+6*3)=36=>so overall for four column addition we get..36 36 36
  +3 +3 +3
  ----------
  39996
  so,the ANSWER IS 3996
  
• 11 years agoHelpfull: Yes(4) No(9)
• Akshay:-why you mul. by 1111
  please explain.......
• 11 years agoHelpfull: Yes(2) No(1)
• anybody tell how to solve this..
  
• 11 years agoHelpfull: Yes(1) No(4)
• a=1,c=3,z=26
  1+3+26+0+1+2+3=36
• 11 years agoHelpfull: Yes(1) No(1)