Consider 23 different coloured beads in a necklace. In how many ways can the beads be placed in the necklace so that 3 specific beads always remain together?

• 21!*3!.total beads=23
  3 beads remain together.
  now total beads=23-3=20.
  consider 3 beads as 1 bead.
  now total beads=21.this can be arranged by 21!way and 3 beads can be interchanged by 3! way.so 21!*3!
• 12 years agoHelpfull: Yes(3) No(0)
• total no of beads=23
  if three taken together then total no:(23-3)=20
  but three taken as 1 so total (20+1)=21
  total arrangement=1/2(21-1)!*3!
• 12 years agoHelpfull: Yes(2) No(0)