Mr. Verma has four different paintings that he wishes to divide among his three children. In how
many different ways can he do this if every child must get at least one painting and all four
paintings are different?
1] 48 2] 18 3] 36 4] 72

• 3 paintings for 3 persons can be distributed in 3! ways.
  the 4th painting can be distributed to 3 people in 3 ways, so that every child would get at least 1 painting with different colours.
  therefore, it could be done in 6*3 = 18 ways.
• 12 years agoHelpfull: Yes(43) No(6)
• he has 4 painting and 3 children
  (4c1*3c1*2c1)*3=72
• 12 years agoHelpfull: Yes(4) No(4)
• 72,each time verma can give in 24 ways so there are 3 children 24*3=72
• 12 years agoHelpfull: Yes(3) No(7)
• 36 is the correct soln
• 11 years agoHelpfull: Yes(3) No(0)
• 4c3*3!*3=72
  
• 12 years agoHelpfull: Yes(2) No(3)
• (4c1*3c1*2c1)*3=72ways
• 11 years agoHelpfull: Yes(2) No(0)
• formula=r^n-rc1(r-1)^n+rc2(r-2)^n-rc3(r-3)^n...................
  so .. 3^4-3c1(3-1)^4+3c2(3-2)^4-3c3(3-3)^4
  81-48+3-0
  84-48
  36 correct answer
• 5 years agoHelpfull: Yes(1) No(0)
• there is a formula n+r-1Cr-1=4+3-1C3-1=6C2=6!/4!2!=5*6/2=15 ways
• 12 years agoHelpfull: Yes(0) No(14)
• admin tell whether answer is 36 or 72
• 11 years agoHelpfull: Yes(0) No(1)
• total ways to distribute 4 different paintings among 3 students is 3/4=81
  but there is 9 possible cases so that, any person may havr 0 paintings, so total ways of distribution is
  81-9 = 72
• 10 years agoHelpfull: Yes(0) No(0)