.Ahmed,babu,chitra,david and eesha each choose a large different number. Ahmed says,"My number is not the largest and not the smallest. "Babu says,"My number is not the largest and not the smallest ."Chitra says,"My number is the largest."David says,"My number is the smallest."Eesha says,"My number is the not the smallest
a.Eesha
b.David
c.Chitra
d.Babu

• what is asked???
  
• 12 years agoHelpfull: Yes(17) No(1)
• ahmed, babu, chitra, david and isha choose a large and different no. ahmed says ‘My number is not the largest and not the smallest’. Babu says “my number is not the largest and the not the smallest”. Chitra says “my number is the largest”. David says “my number is the smallest”. Isha says “my number is the not the smallest”
  Exactly one the five children is lying. The other are telling the truth. Who has the largest number?
  a)isha b)david c)chitra d)babu
• 12 years agoHelpfull: Yes(13) No(8)
• for these king of questions answer will be the last member given in the question
  ie., eesha
  so eesha is answer
  am sure about it
  if any one say dats wrong
  plz u guys prove that
• 12 years agoHelpfull: Yes(12) No(14)
• chitra is ans because.....ahmed and bablu have same statement so it can't be false......if we say.eesha is saying lie...then..eeha's no is smallest which contadicts with david....so chita s lying
• 12 years agoHelpfull: Yes(9) No(9)
• Esha Is the Right answer. Because Chitra is lying. and if the chitra is correct then this is a very simple question and can be solved by a student of 2nd standard as well. So Esha is saying that her No. Is not the smallest one. but rest are saying that our number is not the largest and not the smallest. that's y Esha Is the right option.
• 9 years agoHelpfull: Yes(4) No(0)
• whts asked incomplete question
• 12 years agoHelpfull: Yes(2) No(0)
• ans..b)david
• 12 years agoHelpfull: Yes(1) No(6)
• a.eesha
  because only esha says my number is not smallest i.e. largest
• 8 years agoHelpfull: Yes(1) No(0)
• lets have the positions of largest to smallest from 1to5
  Case 1:
  Assume A-false
  so A must be in 1 or 5
  then B must be in 2 or 3 or 4
  C must be in 1 so A in 5
  but D's statement contradicts with our assumption, so its wrong
  
  CASE 2:
  Assume B-false
  A- 2or3or4
  B- 1 or 5 (since false)
  C- 1 so B-5
  Similarly D's statement contradicts with B's, so wrong
  
  CASE 3:
  Assume C-false
  A- 2 or 3 or 4
  B- 2 or 3 or 4
  C- 2 or 3 or 4 or 5 (since false)
  D- 5 so C- 2 or 3 or 4
  E - 1 or 2 or 3 or 4, since there are already A,B,C in 2 or 3 or 4 ,
  E must be in 1. This satisfies.
  
  Lets try for the remaining 2 cases too
  CASE 4:
  Assume D- false
  A- 2 or 3 or 4
  B - 2 or 3 or 4
  C - 1
  D- 1 or 2 or 3 or 4 (since false) but already C- 1 so 2 or 3 or 4
  Now only left out is 5th place but it contradicts with E's statement , so wrong
  
  CASE 5:
  Assume E - false
  A- 2 or 3 or 4
  B- 2 or 3 or 4
  C - 1
  D- 5
  E's statement is false which means E is the smallest
  but already D-5 so this is also wrong
  
  The only case that satisfies is CASE 3
  
  Hence EESHA has the largest number
• 6 years agoHelpfull: Yes(1) No(0)
• Ans.a. EEsha
  
  Largest -> A B C D E
  A F T/F T/F T/F T/F
  B T/F F T/F T/F T/F
  C F F T F F
  D T/F T/F T/F F T/F
  E T/F T/F T/F T/F T
• 9 years agoHelpfull: Yes(0) No(0)
• Ans-a eesha
• 8 years agoHelpfull: Yes(0) No(0)
• Ans: A
  Largest -> A B C D E
  A F T/F T/F T/F T/F
  B T/F F T/F T/F T/F
  C F F T F F
  D T/F T/F T/F F T/F
  E T/F T/F T/F T/F T
  
  From the above table, If we assume that A has the largest then A and C both are lying. Similarly if we find the truthfullness of the remaining people, it is clear that E has the largest and C lied. (Only one F in the last column)
• 7 years agoHelpfull: Yes(0) No(0)