if x=y=2z and xyz=256 .what is the original number?

• x=8 y=8 z=4
  2z*2z*z=256
  so z=(64)1/3 =4
  z=4
• 12 years agoHelpfull: Yes(10) No(1)
• xyz=256
  4z^3=256
  z^3=64
  z=4
  x=y=8
• 12 years agoHelpfull: Yes(3) No(0)
• x=y=2z
  z=x/2
  xyz=256
  replace y & z by x
  x*x*(x/2)=256
  x^3=512
  x=8=y
  z=x/2=4
  8*8*4=256
• 12 years agoHelpfull: Yes(2) No(0)
• 8
  xyz=256
  x(x)(x/2)=256
  x3=512
  x=8
• 12 years agoHelpfull: Yes(1) No(0)
• xyz=256.
  replace y by x and z by x/2 in the above equation.
  =>x*x*x/2=256
  x^3=256*2
  x^3=512
  x=8
• 12 years agoHelpfull: Yes(1) No(0)
• xyz=256
  4z^3=256
  z^3=64
  z=4
  x=y=8
• 12 years agoHelpfull: Yes(0) No(1)
• x=8 y=8 & z=4
• 12 years agoHelpfull: Yes(0) No(0)
• x=2z, y=2z
  2z*2z*z=256
  4z^3=256
  z^3=64
  z=4
• 12 years agoHelpfull: Yes(0) No(0)
• X=2z, Y=2z, Z=z
  Put these values in XYZ=256
  (2z) (2z) (z) = 256
  4z^3 =256
  Z^3 =64
  Z=4
  X=2z=2*4=8
  Y=2z=2*4=8
  answer is X=8, Y=8,Z=4
• 12 years agoHelpfull: Yes(0) No(0)
• xyz=256
  2z*2z*z=256
  4* z3=256
  z3=64
  z3==4*4*4
  z=4; x=y=8
  
• 12 years agoHelpfull: Yes(0) No(0)
• X=8
  y=8
  z=4
  so we prove
  x=y=2z
  ie.8=8=(2*4)
  ad nxt
  xyz=256
  8*8*4=256
• 11 years agoHelpfull: Yes(0) No(0)
• X=8
  y=8
  z=4
  so we prove
  x=y=2z
  ie.8=8=(2*4)
  ad nxt
  xyz=256
  8*8*4=256
• 11 years agoHelpfull: Yes(0) No(0)
• X=8
  y=8
  z=4
  so we prove
  x=y=2z
  ie.8=8=(2*4)
  ad nxt
  xyz=256
  8*8*4=256
• 11 years agoHelpfull: Yes(0) No(0)
• X=8
  y=8
  z=4
  so we prove
  x=y=2z
  ie.8=8=(2*4)
  ad nxt
  xyz=256
  8*8*4=256
• 11 years agoHelpfull: Yes(0) No(0)
• X=8
  y=8
  z=4
  so we prove
  x=y=2z
  ie.8=8=(2*4)
  ad nxt
  xyz=256
  8*8*4=256
• 11 years agoHelpfull: Yes(0) No(0)
• ans x=8=y,z=4
  
  2z*2z*z=256
  4z^3=2
  z=4
  x=y=2*4=8
  8*8*4=256
• 11 years agoHelpfull: Yes(0) No(0)
• 8Z^3=256
  Z^3=64
  X=Y=2Z=8
  
  
• 11 years agoHelpfull: Yes(0) No(0)
• 2z*z*z=256
  z=4
  y=8
  x=8
• 11 years agoHelpfull: Yes(0) No(0)
• 2z*2z*z=256
  4z^3=256
  z^3=64
  z=4
• 10 years agoHelpfull: Yes(0) No(0)