A & B starts from their house at 10 am at 20 kmph and 40 kmph respectively. There is a T junction on their path A turn left at T junction at 12.00 non. B reaches T junction earlier and turns right. Distance between A & B ?

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  x--------------y
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  distance travelled by A till 12.00 noon is d=s*t
  d=20*2//(12.00-10.00)
  d=40km
  ie distance between xand y is 40
  so time taken by B to travel this 40 km is
  t=d/s;t=40/40;t=1
  so B travelled xy in one hour(till 11.00) and in rest one hour (ie till 12),the distance travelled is d=s*t; d=40*1; d=40
  so the distance between A and B is 40km
• 12 years agoHelpfull: Yes(36) No(12)
• ans is
  40 km
• 12 years agoHelpfull: Yes(10) No(6)
• Distnace between House and T junction = 20 x 2 = 40.
  ie., B reached T at 11 am.
  B continued to right after 11 am and travelled upto 2. So distance covered by him = 3 x 40 = 120
  A reached T at 12 noon and travelled upto 2 So distanced travelled by him = 2 x 20 = 40
  So total distance between them = 120 + 40 = 160 km
• 9 years agoHelpfull: Yes(9) No(0)
• Ans might be 40km
  
• 12 years agoHelpfull: Yes(7) No(6)
• ans is 40km
  
• 12 years agoHelpfull: Yes(5) No(3)