44^44/8^n gives no reminder..
n=?

• 44^44/8^n
  =(4*11)^44/8^n
  =(11^44)*(4^44)/(2^3)^n
  =(11^44)*(2^88)/(2)^3n
  now 11^44 can not be divided by 2^3n as bcoz there is no even last digit in 11^44
  so 2^88 will be divided by 2^3n
  so 3n=88
  n=29...
  n will have value 1 to 29
• 12 years agoHelpfull: Yes(14) No(1)
• n=1-22, 44^44= (4*11)^44 = (11^44)*(4^44)=(11^44)*(16)^22=(11^44)*(2*8)^22 =(11^44)*(2^22)*(8^22) so any value of n from 1 to 22 will give no remainder
• 12 years agoHelpfull: Yes(4) No(5)