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if (p/q)-(q/p)=21/10
then what ia the value of(4p/q)+(4q/p)
options:
1. 58/5
2. 59/5
3.121/105
Read Solution (Total 17)
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- Anyone got sms or mail regarding tcs off campus, which was on march 2nd?
- 9 years agoHelpfull: Yes(21) No(7)
- p/q =a then q/p = 1/a
a+1/a=21/10
by solving this we get a=5/2
then 4*5/2+4*2/5 = 58/5 (Answer) - 9 years agoHelpfull: Yes(18) No(1)
- let p/q=a then q/p=1/a
a - (1/a)=21/10
(a^2 -1)/a=21/10
10(a^2)-10=21a
10(a^2)-10-21a=0
10(a^2)-25a+4a-10=0
5a(2a-5)+2(2a-5)=0
5a+2=0 ; 2a-5=0
2a-5=0
a=5/2
=>4(5/2)+4(2/5)
(20/2)+(8/5)
(100+16)/10
=>58/5
- 9 years agoHelpfull: Yes(11) No(0)
- apply the formula (a-b)^2 =(a+b)^2+4ab
u will get 58/5
i did it...answer is 58/5 - 9 years agoHelpfull: Yes(3) No(9)
- I think answer is option 1. 58/5
- 9 years agoHelpfull: Yes(2) No(1)
- can anyone suggest how to prepare for tcs off capus which is on 2nd???
- 9 years agoHelpfull: Yes(2) No(0)
- how will we know dat we are shortlisted for tcs test which is going to be held in 2nd march...i got the mail that "your detail is under validation".
- 9 years agoHelpfull: Yes(2) No(0)
- Yes, I got
- 9 years agoHelpfull: Yes(1) No(0)
- plz explain how it is 58/5
- 9 years agoHelpfull: Yes(1) No(1)
- yes i can receive
- 9 years agoHelpfull: Yes(1) No(2)
- just check it out in tcs next step portal @annu priya
- 9 years agoHelpfull: Yes(1) No(0)
- Which batch are you ppl from??
- 9 years agoHelpfull: Yes(0) No(0)
- Let p/q = a, then (a - 1/a) = 21/10
⇒a2−1=a.2110
⇒10a2−21a−10 = 0
Roots of the equation = −b±b2−4ac−−−−−−−√2a
a = 21±441+400−−−−−−−−√20
a = 21±2920 = 5/2 or -2/5
For a = 5/2, 4p/q+4q/p = 58/5
For a = -2/5, 4p/q+4q/p = -58/5 - 9 years agoHelpfull: Yes(0) No(0)
- Let p/q = a, then (a - 1/a) = 21/10
⇒a2−1=a.2110
⇒10a2−21a−10 = 0
Roots of the equation = −b±b2−4ac−−−−−−−√2a
a = 21±441+400−−−−−−−−√20
a = 21±2920 = 5/2 or -2/5
For a = 5/2, 4p/q+4q/p = 58/5
For a = -2/5, 4p/q+4q/p = -58/5 - 9 years agoHelpfull: Yes(0) No(0)
- (P/q)-(q/p)=21/10
Solve it (p^2-q^2)/pq=21/10
Pq gives 10 it means values can be 5 and 2
And 5 and 2 satifies p^2-q^2 which is 21
So p=5 and q=2
Now 4×(5/2 + 2/5)
Gives ans 58/5. - 9 years agoHelpfull: Yes(0) No(1)
- let us take p/q=x and q/p=1/x
x-1/x=21/10
then by solving we get a quadratic equation like 10x^2-10-21x=0
10x^2-25x+4x-10=0
then by taking factors we get two values for x,x=-2/5 and x=5/2
by substituting x=5/2
4(5/2)+4(2/5)=58/5 - 6 years agoHelpfull: Yes(0) No(0)
- Take p/q as x. so x-1/x=21/10. from there find x and get 5/2 and put it in the form get the answer it will be 58/5
- 6 years agoHelpfull: Yes(0) No(0)
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