a urn has 15 balls numbered from 1 to 15.when the ball is picked then it is again replaced.the probability that an odd and an even numberd ball is picked and replaced it?

• no of odd balls=1,3,5,7,9,11,13,15 (i.e means 8 odd balls are here)
  no of odd ball=2,4,6,8,10,12,14(i.e means 7 even balls)
  now total balls=15
  probability is=(8/15)*(7/15)=56/225
• 9 years agoHelpfull: Yes(32) No(2)
• 8/15 *7/15 =56/225
• 9 years agoHelpfull: Yes(16) No(5)
• can smbody elaborate it.. its not clear????????????
• 9 years agoHelpfull: Yes(7) No(3)
• no. of even balls=7 no. of odd balls=8
  prob of picking a even ball= 7/15 and that of odd is 8/15
  so, the probability that an odd and an even numberd ball is picked and replaced is 7/15 * 8/15
  
• 9 years agoHelpfull: Yes(6) No(0)
• no. of odd balls=8, no. of even balls=7
  probability of taking odd balls =8/15
  probability of taking even balls=7/15
  probability 0f taking an odd ball and even ball=(8/15)*(7/15)
• 9 years agoHelpfull: Yes(6) No(0)
• answer is 0.we cant pick a ball numbered with both odd and even
• 9 years agoHelpfull: Yes(1) No(26)
• probability of odd ball getting picked == 8/15
  
  no the urn have 14 balls ..
  probability of even ball getting picked = 7/14 = 1/2
  
  so answer = 8/30 = 4/15
• 9 years agoHelpfull: Yes(1) No(21)
• 26 its answer
• 9 years agoHelpfull: Yes(0) No(24)