A man whose age is 45 yrs has 3 sons named John, Jill, jack. He went to a park weekly twice. He loves his sons very much. On a certain day he found the shop keepers selling different things. An apple cost 1penny, 2chocalate costs 1penny & 3 bananas cost 1 penny. He has bought equal number of apple, chocolate & banana for each son. If the total amount he invest is 7 penny then how many he has bought from each piece for his son?
a) 1app, 1cho, 1 banana b)1 app, 2cho,3 banana c)1app, 2cho, 1banana

• 3 app=3 penny
  6 cho=3 penny
  3 banana= 1 penny
  so total 7 penny
  so 1 app,2 cho,1banana
• 14 years agoHelpfull: Yes(51) No(0)
• easiest way to find ans:
  he has 3 sons and 7 penny to equally divide among his sons... so 7/3=2.33
  check in the options which equls to 2.33
  so c) has 1app+2cho+1banana= 1+1+1/3
  =1+1+.33=2.33
  so c) is the ans
• 14 years agoHelpfull: Yes(19) No(2)
• c)
  
  as he buys equal items for each son
  we can divide 3 bananas equally 1 each(so 3 bananas=1penny)
  we require min 6 choc for equal distribution(so 6 choc=3 penny)
  we require min 3 apples for equal distribution(so 3 apples=3 penny)
• 14 years agoHelpfull: Yes(8) No(1)
• c)1app, 2cho, 1banana
• 14 years agoHelpfull: Yes(5) No(2)
• cost for one son is 7/3 =2.33
  1 apple= 1 penny
  1 choc. = 1/2= 0.5 penny
  1 bana. = 1/3= 0.33
  
  so 1apple + 2 choc. + 1 bana. = 1+1+0.33= 2.33
  
  hence correct ans. is (c)
• 9 years agoHelpfull: Yes(0) No(0)
• 1 apple,2 chocolates, 1 banana for each son..
  total amount = 3 penny +3 penny+ 1 penny.
• 9 years agoHelpfull: Yes(0) No(0)