274+23n=any even value, find value of n?

• even +even= even,
  hence 274(even)+23n(must be even)
  hence n must be any even num
• 11 years agoHelpfull: Yes(19) No(0)
• i think n can b any even integer.
  bcz fr every even value of n,274+23n is even.
• 11 years agoHelpfull: Yes(7) No(3)
• let x is even number
  274+23n=x
  n=(x-274)/23
  if x=274then n=0
  if x=297then n=1
  if x=310then n=2
  ...
  ..
  hence n can be 0,1,2,3,4,5,6,7,8,9,10,11,12....
• 11 years agoHelpfull: Yes(1) No(17)
• odd*odd=always odd even*even=always even....odd*even=always odd............so n could b any even no starting frm 0....n=0,2,4,6,8,10........................
• 11 years agoHelpfull: Yes(1) No(4)
• in my sol
  since x is even hence n can be any even number
• 11 years agoHelpfull: Yes(1) No(1)
• even no including 0 .as even+even =even & odd*even=even .so when 23 is multiplied by any even no it result in even and when this obtained even no is added in 274 result in even
• 11 years agoHelpfull: Yes(0) No(0)