A person drive with constant speed and after sometime he sees a milestone with 2 digits.then aftr one hr, travelling with same speed sees same 2 digit in reverse order.1 hr later,he sees that the milestone has a same 2 digits with 0 in btwn them. what s the speed of the car?

• Let the digits on the first milestone be =10x+y.
  Digits on the second milestone = 10y+x
  Digits on the third milestone = 100x+y.
  
  now as the speed is constant distance covered in 1 hour will be equal between 1st,2nd milestone AND 2nd,3rd milestone!!!
  therefore, (100x+y)-(10y+x)=(10y+x)-(10x+y)
  108x = 18 y
  (x/y)=6/1
  as x and y are single digit nos. , x=6 and y=1!!!!
  now milestone are 16 , 61,106 ...speed =((61-16)/1)=45kmph
• 12 years agoHelpfull: Yes(90) No(1)
• Answer is 45.
  as first milestone shows 16
  second milestone shows 61 (61-16=45)
  third milestone shows 106 (106-61=45)
  
• 12 years agoHelpfull: Yes(19) No(7)
• helooow...if i choose.........12 and 21 and 102...it's nt same...!
• 12 years agoHelpfull: Yes(2) No(3)
• ans is 45 km/hr
  suppose at some time it travells by hit &trial 16 then adding 45 to it results 61 again adding 45 results 106 which fulfill required criteria.
• 12 years agoHelpfull: Yes(2) No(1)
• thnx gurdeep for explaining
• 12 years agoHelpfull: Yes(1) No(0)