An=A(n-1)-A(n-2) where, An is the nth term in the sequence,n is an integer n>=3,A(1)=1,A(2)=1,.Calculate S(1000) where, S(1000) is the sum of 1st 1000 terms.

• a3=a2-a1=0
  a4=a3-a2=-1
  a5=a4-a3=-1
  a6=a5-a4=0
  a7=a6-a5=1
  a8=a7-a6=1
  a9=a8-a7=0
  cycle is repeating after 6 terms
  so, 1000/6=166 and remainder 4
  so 1+1+0+(-1)=1
  so ans is 1
  
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