1,2,3,4,5,6,7,8,9,1,0,1,1,1,2,1,3,1,4,1,5....find 25322 term?

• ans is 6.
  explanation- 1 to 100 - 192 term
  101 to 1000- 2701 term
  1001 to 6500-22000 term
  so 25322-(192+2701+22000)=429th term have to find
  6501 to 6600 = 400 term
  6601 to 6607 = 28 term
  s0 next term is 6608.
  so ans is 6.
  
• 11 years agoHelpfull: Yes(15) No(1)
• see
  the series is 1,2,3,4,5,6,7,8,9=9 terms
  and further 1,0,1,1,1,2,1,3,1,4,1,5,1,6,1,7,1,8,1,9........9,9=180 terms
  (just take the series as 10,11,12,13,14,15,,,,,99 then the no. of term in this series is=90 therefore the original no. of term in the series 1,0,1,1,2,1,3,1,4,,,,,,,,,,9,9=180)
  similarily for 1,0,0,1,0,1,,,,,,,,,,,,,,9,9,9 no. of terms=900*3=2700
  note that so far we have find total 2899 terms and we have o find (25322-2899=22423th term from here on)
  further the series is 1,0,0,0,1,0,0,1,,,,,,,,,9,9,9,9= total 9000*4=36000terms
  now in the above series we have to find the 22423th term
  thus 36000-22423=13577
  13577/4=3394.25
  thus the 3394th term is 10000+(3394-1)*1=13393
  next is 13394 thus the 25322th term is=1
• 11 years agoHelpfull: Yes(13) No(16)
• 1,2,3.....9=9 terms
  1,0,1,2,.....9,9=90*2=180 terms
  1,0,0,1,0,1......9,9,9=900*3=2700 terms
  2700+180+9=2899
  remaining terms:25322-2889=22433
  
  so no. of 4 digit numbers:22432/4=5608
  thus the 25321 term will be 999+5608=6607
  
  next number is(6,6,0,8)
  Ans=25322 term will be 6
• 11 years agoHelpfull: Yes(9) No(0)
• no. of terms from 1 to 9= 9*1=9
  no. of terms from 10 to 99 = 90*2 = 180
  no. of terms from 100 to 999 = 900*3= 2700
  no. of terms from 1000 to 9999 = 9000*4 = 36000
  
  now, add first three...i.e 9+180+2700= 2889
  there are 2889 terms from 1 to 999
  
  how more we need--->> 25322-2889= 22,433
  
  as there are 4 digits in each term from 1000 above, divide 22,433 by 4
  
  (or else divide 22,432 by 4...coz it completely divides it)
  
  22,432/4 = 5,608 (including 1000)
  
  so, 999+5608=6607
  first '6' in 6607 is 25321st term....so the next '6' is 25322nd term...:)
  
  m i wrong??
• 11 years agoHelpfull: Yes(4) No(2)
• 1 dgt -> 9
  2 dgt -> (10-99)=90*2(each contain 2 term)
  likewise
  3 dgt -> 900*3
  4 dgt -> 9000*4=36000 (>25322) so skip here..
  add all above three..
  sum=2889
  (25322-2889)=22433
  22433/4= 5608.25=5609th 4 dgt no.
  thus ans will be =1000+5608=6608(since 1000 is included that' why it is 5609th term)
  thus term will be 8...
• 11 years agoHelpfull: Yes(3) No(6)
• total numbers upto 3 digit are 9+90*2+900*3=2889
  25322-2889=22533
  as all no will be of 4 digits now so rank of no will be
  22533/4=5633.25
  means that desired no will be the first term of 5634th no in 4 degit series so
  5634 no=1000+(5634-1)1=6633
  hence required ans is 6
• 11 years agoHelpfull: Yes(2) No(1)
• SORRY GUYS FOR EARLY MISHAP:
  HERE IS THE SOLUTION-
  1,2,3,4,5,….9 total terms=9
  1,0,1,2,1,3,1,4,,,,,,,,,9,9 total terms=90*2=180
  1,0,0,1,1,1,1,1,2,,,,,,9,9,9 total terms=900*3=2700
  Thus sofar we have came to 2889th term i:e,9
  Now 1,0,0,0,1,0,0,1,1,0,0,2,,,,,,,,,,,,,,,,,,,9,9,9,9
  Total terms=9000*4=36000
  But we have to stop the discussion at 25322-2889=22433th term
  Thus we will find 22433th term in the above series
  22433/4=5608.75
  Now the 5608th term in the series1000,1001,,,,,,,,,,,,,,,9999
  Is=1000+(5608-1)*1=6607
  Rank of 6607 in the series1,0,0,0,1,0,0,1,,,,,,,,,9,9,9,9 is=5608*4=22432
  Thus 22432+2700+180+9=25321th term
  Now the 25322th term will be in 6,6,0,8
  Thus 25322th term is 6……
  
• 11 years agoHelpfull: Yes(2) No(0)
• goldy has done little mistake he shud hve subtracted from 10000 not added as u r counting from back...6605 is what u get,ans shud be 0
• 11 years agoHelpfull: Yes(1) No(2)
• can any xplain it...
  
• 11 years agoHelpfull: Yes(0) No(1)
• ans 9
  because 4091th=999 ie9
  then 21228 digit are left and
  
• 11 years agoHelpfull: Yes(0) No(4)
• @GOLDY pls xplain the last 3 lines.
• 11 years agoHelpfull: Yes(0) No(1)
• @goldy how 2899 came 9+180+2700=2889 only rite,then last step is not clear please explain
  
• 11 years agoHelpfull: Yes(0) No(0)
• any other method to solve ??
• 11 years agoHelpfull: Yes(0) No(0)
• @goldy please explain last three line of urs??
  
• 11 years agoHelpfull: Yes(0) No(0)
• plz yyr xplain properly nt able 2 get the solution correctly
• 11 years agoHelpfull: Yes(0) No(0)
• 1,2,3,...... in this series we cn see that 10th term 1 30th term is 2 50th term is 3 so 10+(n-1)*20=25310
• 11 years agoHelpfull: Yes(0) No(0)
• 25310
• 11 years agoHelpfull: Yes(0) No(0)
• i dont know why but the full solution is not coming........ last time i am trying 25310
• 11 years agoHelpfull: Yes(0) No(0)
• n=1266 again 1+(1266-1)*1=1266 so 2310th term is 1 next is 2 then 6 so 2322nd term is 1.
• 11 years agoHelpfull: Yes(0) No(0)