IBM
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Numerical Ability
Algebra
Q. Find last two digits of 121*123*125*127*129 ?
Read Solution (Total 5)
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- ans>25
multiply last two digit of every no
25*21 gives last two digit as 25
again 25*29 gives last two digit as 25
25*23 gives 75 as last two digit
now 75*27 gives last two digit as 25
hence 25 is answer - 9 years agoHelpfull: Yes(14) No(2)
- ans:25
121*123*125*127*129=30478523625 - 9 years agoHelpfull: Yes(4) No(1)
- ans wiil be 131
- 9 years agoHelpfull: Yes(1) No(9)
- multiply all then last 2 digits is 35
- 9 years agoHelpfull: Yes(0) No(7)
- ans : last two digit of 30478523625 is 25
- 9 years agoHelpfull: Yes(0) No(0)
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