Tell me..how to find no.of zeros in 50!

• Divide by 5: 50/5-->10
  Divide by 5^2: 50/25-->2
  Sum all the divisions: 10+2=12
  number of zeros up to 50! = 12
• 9 years agoHelpfull: Yes(15) No(0)
• we have to count occurrence of digit 5 in the given factorial to count the number of zeros.
  for example: in 50! we have
  5,10,15,20,25,30,35,40,45,50 these many multiples of 5.
  
  for 25 we have 5*5: count is 2
  same is for 50- 5*5*2 :count is 2
  for others count is 1. so total count of 5 is 12. this is the answer
• 9 years agoHelpfull: Yes(3) No(4)
• formula for no of zeros
  n/5+n/5^2+n/5^3+....and so on ,we count only integaral value ...here we have to find no of zeros in 50
  50/5+50/5^2+50/5^3+....=10+2=12 answer because we will not count 50/5^3 as integral value.
• 7 years agoHelpfull: Yes(1) No(0)