f(f(n)+f(n)=2n+3, f(n)=0 where n is an integer,f(2012)?

• f(m)=f(n)where m#n
  then-
  f(m+f(n))=2*f(n)
  2*f(n)=2*n+3
  f(n)={2*n+3}/2......eqn(1)
  f(n)=0(given)
  from eqn(1):-
  u can find d value of f(2012).
  
  
  
• 12 years agoHelpfull: Yes(4) No(4)
• f(n)=0
  n is an integer,
  so f(2012)=0;
  
• 12 years agoHelpfull: Yes(4) No(1)
• f(1)=2
  f(2)=3 then
  f(2012)=2013
• 12 years agoHelpfull: Yes(4) No(0)
• i think 0 ........
• 12 years agoHelpfull: Yes(3) No(6)
• f(n)=2n+3
  f(2012)=2012*2+3=4027
• 12 years agoHelpfull: Yes(1) No(2)
• @moumita adak ...........options plz
• 12 years agoHelpfull: Yes(0) No(0)