TCS Company Numerical Ability Ratio and Proportion

ratio proportion problem on age...

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a=surface area of 6 faces=(9*9)*6
b=surface area of all holes at faces=(3*3)*6
c=surface area of insides=(9*3)*4*3
d=surface area of square at junction of 3 tunnels=(3*3)*6
therefore, final surface area after cutting=a-b+c-d
=486-54+324-54=702.
11 years agoHelpfull: Yes(1) No(4)

TCS Other Question

A cube of length 9cm is given. Square holes of length 3cm centered in each face are cut through to the opposite face. The edges of the hole are parallel to the edges of the cube (see figure). The surface area of the cube including the insides (in sq cm) is

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