101102103104..................................148149150
what is the remainder when this number divided by 9?

• The divisibility rule for 9 is sum of the digits is to be divisible by 9. So
  
  We calculate separately, sum of the digits in hundreds place, tenths place, and units place.
  
  Sum of the digits in hundreds place: 1 x 50 = 50
  
  Sum of the digits in tenths place : 0 x 9 + 1 x 10 + 2 x 10 + 3 x 10 + 4 x 10 + 5 x 1 = 105
  
  Sum of the digits in units place : (1 + 2 + 3 + ...+ 9) x 5 = 225
  
  So total = 380
  
  So remainder = 380 / 9 = 2
• 9 years agoHelpfull: Yes(10) No(5)
• when we add the digit and divide it by 9 then remainder will be 2
  
  
• 9 years agoHelpfull: Yes(3) No(3)
• can you explain the solution clearly..
• 9 years agoHelpfull: Yes(3) No(2)
• 2 .when the number is added and divided by 9
  
• 9 years agoHelpfull: Yes(1) No(1)
• Ans: 2
  101 to 150 sum of digits = 50 1's + 50(50+1)/2 = 1325
  sum of digits in 1325 = 11
  sum of digits in 11 = 2
  .". remainder = 2
• 9 years agoHelpfull: Yes(1) No(1)
• plz explain the solution clearly...
• 9 years agoHelpfull: Yes(0) No(0)