: A team won 80% of its matches total played. It played 5 matches more of which it won 3 and lost 2. The losing percentage changed to 25%. How many matches it played totally?
1)14
2)16
3)20
4)35

• lil change
  let earlier it played x matches
  lossing=0.2x
  atq
  (.2x+2)/(x+5)=25/100
  solving x=15
  total mach played=15+5=20
• 12 years agoHelpfull: Yes(61) No(2)
• Let initally no. of played matches=x
  won mathes=80% of x=(80/100)*x
  after 5 mates more....
  total matches played=x+5
  won matches becomes=[(80/100)*x]+3
  and at last % of lost matches=25%
  so % of won matches=75%
  thus....
  (75/100)*(x+5)=[(80/100)*x]+3
  By solving it...
  we get x=15
  thus total no of matches played=x+5=15+5=20
  so ans=20
• 12 years agoHelpfull: Yes(7) No(0)
• let earlier it played x matches
  lossing=0.2x
  atq
  (.2+2)/(x+5)=25/100
  solving x=15
  total mach played=15+5=20
• 12 years agoHelpfull: Yes(5) No(1)
• I think ans. is 35
• 12 years agoHelpfull: Yes(2) No(11)
• 20 IS CORRECT ANS.
• 12 years agoHelpfull: Yes(2) No(1)
• 15 i think
• 12 years agoHelpfull: Yes(1) No(6)
• 20 suppose match win be x & lost be y then 4/5=x/x+y & 3/4=x+3/x+y+5 solving x=12 y=3 so total 12+3+5=20
  
• 12 years agoHelpfull: Yes(1) No(0)