In how many ways a team of 11 must be selected from 5 men and 11 women such that the team must comprise of not more than 3 men?
a. 1565
b. 1243
c. 2256
d. 2456

• c.2256
  (5c3*11c8+5c2*11c9+5c1*11c10+11c11)
• 9 years agoHelpfull: Yes(15) No(0)
• 3 mangoes and 4 apples costs Rs 85. 5 apples and 6 peaches costs Rs. 122. 6 mangoes and 2 peaches cost Rs.114. what is the combined price of 1 apple, 1peach and 1 mango?
  (a)37
  (b)39
  (c)35
  (d)36
  28
  27
  26 canu any tell me the ans of this question
• 9 years agoHelpfull: Yes(12) No(0)
• As we can take "atmost" 3 Men. So Combinations of (Men,Women) will be {(0,11),(1,10),(2,9),(3,8)}
  Therefore --> 11C11 + 5C1 x 11C10 + 5C2 x 11C9 + 5C3 x 11C8
  --> 2256
• 9 years agoHelpfull: Yes(6) No(0)
• (5C0*11C11 ) + (5C1*11C10) + (5C2*11C9) + (5C3*11C8) = 2256
• 9 years agoHelpfull: Yes(3) No(0)
• 1 apple +1 mango + 1 peaches = 37
• 9 years agoHelpfull: Yes(2) No(0)
• 1 Apple =10
  1Mango=15
  1Peaches=12
  1Apple+1Mango+1Peaches=37
• 9 years agoHelpfull: Yes(2) No(0)
• Dear @Ramya,
  Note: It is 114 not 144.
  3m + 4a = 85 ..(1)
  5a + 6p = 122 ..(2)
  6m + 2p = 114 ..(3)
  (1) x 2 => 6m + 8a = 170
  (3) => 6m + 2p = 114
  Solving we get 8a - 2p = 56 ..(4)
  (2) => 5a + 6p = 122
  3 x (4) = 24a - 6p = 168
  Solving we get a = 10, p = 12, m = 15
  So a + p + m = 37
• 9 years agoHelpfull: Yes(2) No(0)
• ways of selection : 5c4 x 11c7 + 5c5 x 11c6
• 9 years agoHelpfull: Yes(0) No(3)
• 5c3*11c8+5c2*11c9+5c1*11c10+5c0*11c11 = 2256
  
  Hence, c. 2256
• 9 years agoHelpfull: Yes(0) No(0)